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IOQM 2026 class 1 - Parity and power of integers

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Q1: Find all nonnegative integers \( n \) such that there are integers \( a \) and \( b \) with the property \[ n^2 = a + b \quad \text{and} \quad n^3 = a^2 + b^2. \] Solution: Using QM-AM inequality, \[ \frac{a + b}{2} \le \sqrt{\frac{a^2 + b^2}{2}}. \] Substitute \( a + b = n^2 \) and \( a^2 + b^2 = n^3 \): \[ \frac{n^2}{2} \le \sqrt{\frac{n^3}{2}}. \] Squaring both sides: \[ \frac{n^4}{4} \le \frac{n^3}{2}. \] Simplify: \[ \frac{n}{2} \le 1. \] Thus, \[ n \le 2. \] So \( n = 0, 1, 2 \). Q2: In each box of a \(15 \times 15\) square table one of the numbers \(1,2,3,\dots,15\) is written. Boxes which are symmetric with respect to one of the main diagonals contain equal numbers, and no row or column contains two copies of the same number. Show that no two of the numbers along the main diagonal are the same. Solution: Sample 3x3 matrix: [1,2,3] [3,1,2] [2,3,1] Consider a smaller \(3 \times 3\) matrix to understand the structure. Let the matrix be symmetric about a...

number theory zoom class 4

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  Q1: Q2:

number theory zoom class 3

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  LCM is defined for all integers but it will always be positive by definition. LCM is only defined for integers not for irrational numbers. a*b = lcm(a,b) * gcd(a,b) will hold only for 2 numbers. Not for 3 or more numbers. similarly find solutions for 

number theory zoom class 2

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  d != 2,3,7,8 since no perfect square ends in these digits. d != 1 since that will give remainder 3 div by 4 but P.S. mod 4 = 0,1 and using the similar logic d != 5,6,9 Only values of d = 0,4 So 22 such perfect squares which are 3 digits. Case 2: d = 4 So here we are multiplying 3 numbers, each of which is a multiple of 3 but not a multiple of 9. So eventually after multiplying all 3 we will get a number which will be 27*something. A p.s. should have even power of each factor. So it's not a perfect square.