Kite Diagonals properties with proof

1. Diagonals of a kite meet at 90 Deg.
2. The diagonal joining vertices between unequal sides gets bisected by the other diagonal.

Proof:

In a kite ABDC,
AB = AC
DB = DC

Diagonals AD and BC meet at E.

ABD and ACD are congruent by SSS.
So Angle  BAD = Angle CAD
Which is same as saying that
angle BAE = angle CAE

Now ABE and ACE are congruent by SAS.
So angle AEB = AEC
Since AEB + AEC = 180 so AEB = AEC = 90, H.P.

Using this congruence of ABE and ACE, we also prove that BE = EC,
i.e. the diagonal joining vertices between  unequal sides gets bisected by the other diagonal.

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